(4x^2-5x-6)/(x^3-4x)

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Solution for (4x^2-5x-6)/(x^3-4x) equation:


D( x )

x^3-(4*x) = 0

x^3-(4*x) = 0

x^3-(4*x) = 0

x^3-4*x = 0

x^3-4*x = 0

x*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x = 0

x = 0

x in (-oo:-2) U (-2:0) U (0:2) U (2:+oo)

(4*x^2-(5*x)-6)/(x^3-(4*x)) = 0

(4*x^2-5*x-6)/(x^3-4*x) = 0

4*x^2-5*x-6 = 0

4*x^2-5*x-6 = 0

DELTA = (-5)^2-(-6*4*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)+5)/(2*4) or x = (5-121^(1/2))/(2*4)

x = 2 or x = -3/4

(x+3/4)*(x-2) = 0

x^3-4*x = 0

x*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x*(x-2)*(x+2) = 0

((x+3/4)*(x-2))/(x*(x-2)*(x+2)) = 0

( x+3/4 )

x+3/4 = 0 // - 3/4

x = -3/4

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 2}

x = -3/4

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